Como fatorar e resolver # 2x ^ 2 + x - 1 = 0 #?
Responda:
#x=1/2# or #x=-1#
Explicação:
#2x^2+x-1=0#
Fatore.
#2x^2+2x-x-1=0#
#2x(x+1)-1(x+1)=0#
#(2x-1)(x+1)=0#
#2x-1=0# or #x+1=0#
#x=1/2# or #x=-1#
#x=1/2# or #x=-1#
#2x^2+x-1=0#
Fatore.
#2x^2+2x-x-1=0#
#2x(x+1)-1(x+1)=0#
#(2x-1)(x+1)=0#
#2x-1=0# or #x+1=0#
#x=1/2# or #x=-1#