Como resolver # (x + 5) -2 (4x-1) = 0 #?
Responda:
#x=1#
Explicação:
#(x+5) - 2 ( 4x - 1) = 0#
#(x+5) - 2 * ( 4x - 1) = 0#
#x+5 + (-2) * (4x) + ( -2) * (- 1) = 0#
#x+5 -8x +2 = 0#
#x-8x +2 + 5= 0#
#-7x + 7= 0#
#-7x = - 7#
#x = (-7)/(-7)#
#x=1#
#x=1#
#(x+5) - 2 ( 4x - 1) = 0#
#(x+5) - 2 * ( 4x - 1) = 0#
#x+5 + (-2) * (4x) + ( -2) * (- 1) = 0#
#x+5 -8x +2 = 0#
#x-8x +2 + 5= 0#
#-7x + 7= 0#
#-7x = - 7#
#x = (-7)/(-7)#
#x=1#