# Qual é a derivada de  y = sec (x ^ 2) ?

y'=2x*sec(x^2)tan(x^2)

Solution

let's y=f(g(x))

Using Chain Rule, we get

y'=f'(g(x))*g'(x)

for given problem, which is

y=sec(x^2)

differentiating with respect to x using Chain Rule,

y'=sec(x^2)tan(x^2)*(x^2)'

y'=sec(x^2)tan(x^2)*2x

y'=2x*sec(x^2)tan(x^2)