# What are the bond angles in the central atom of the following: "NSF", "OF"_2, and "IBr"_2^−"?

#### Responda:

The bond angles are slightly less than 120°, slightly less than 109.5 °, and 180 °, respectively.

#### Explicação:

bb"NSF"

A estrutura de "NSF" is

There is a lone pair on the "N" atom, a lone pair on the "S" atom, and there are three lone pairs on the "F" átomo.

Esta é uma "AX"_2"E" molecule, so the electron geometry is trigonal planar and the molecular shape is bent.

The theoretical bond angle is 120 °, but repulsion by the lone pairs decreases the bond angle to about 117 °.

bb"OF"_2

A estrutura de Lewis "OF"_2 is

Esta é uma "AX"_2"E"_2 molecule, so the electron geometry is tetrahedral and the molecular shape is bent.

The theoretical bond angle is 109.5 °, but repulsions by the lone pairs decrease the bond angle to about 103 °.

bb"IBr"_2^-

A estrutura de Lewis "IBr"_2^- is

Esta é uma "AX"_2"E"_3 structure, so the electron geometry is trigonal bipyramidal.

The lone pairs occupy the equatorial positions, with the "Br" atoms in the axial locations.

The bond angle is 180 °.