What are the bond angles in the central atom of the following:
#"NSF"#,
#"OF"_2#,
and #"IBr"_2^−"#?

Responda:

The bond angles are slightly less than 120°, slightly less than 109.5 °, and 180 °, respectively.

Explicação:

#bb"NSF"#

A estrutura de #"NSF"# is

upload.wikimedia.org

There is a lone pair on the #"N"# atom, a lone pair on the #"S"# atom, and there are three lone pairs on the #"F"# átomo.

Esta é uma #"AX"_2"E"# molecule, so the electron geometry is trigonal planar and the molecular shape is bent.

The theoretical bond angle is 120 °, but repulsion by the lone pairs decreases the bond angle to about 117 °.

#bb"OF"_2#

A estrutura de Lewis #"OF"_2# is

cnx.org

Esta é uma #"AX"_2"E"_2# molecule, so the electron geometry is tetrahedral and the molecular shape is bent.

The theoretical bond angle is 109.5 °, but repulsions by the lone pairs decrease the bond angle to about 103 °.

upload.wikimedia.org

#bb"IBr"_2^-#

A estrutura de Lewis #"IBr"_2^-# is

i.ytimg.com

Esta é uma #"AX"_2"E"_3# structure, so the electron geometry is trigonal bipyramidal.

lessons.chemistnate.com

The lone pairs occupy the equatorial positions, with the #"Br"# atoms in the axial locations.

The bond angle is 180 °.

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