Y = x ^ 2-6x + 7 no formulário de vértice?

Responda:

y=(x-3)^2-2

Explicação:

"the equation of a parabola in "color(blue)"vertex form" is.

color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))

"where "(h,k)" are the coordinates of the vertex and a"
"is a multiplier"

"given the parabola in "color(blue)"standard form";y=ax^2+bx+c

"then the x-coordinate of the vertex is"

•color(white)(x)x_(color(red)"vertex")=-b/(2a)

y=x^2-6x+7" is in standard form"

"with "a=1,b=-6" and "c=7

x_("vertex")=-(-6)/2=3

"substitute this value into the equation for y"

y_("vertex")=9-18+7=-2

(h,k)=(3,-2)

y=(x-3)^2-2larrcolor(red)"in vertex form"