Como você condensa 2 no 4 - no 2 2no4−no2?
Responda:
2ln4-ln2=ln82ln4−ln2=ln8
Explicação:
As alnb=lnb^aalnb=lnba e lnp-lnq=ln(p/q)lnp−lnq=ln(pq)
2ln4-ln22ln4−ln2
= ln4^2-ln2ln42−ln2
= ln16-ln2ln16−ln2
= ln(16/2)=ln8ln(162)=ln8
2ln4-ln2=ln82ln4−ln2=ln8
As alnb=lnb^aalnb=lnba e lnp-lnq=ln(p/q)lnp−lnq=ln(pq)
2ln4-ln22ln4−ln2
= ln4^2-ln2ln42−ln2
= ln16-ln2ln16−ln2
= ln(16/2)=ln8ln(162)=ln8