Como você condensa #2 no 4 - no 2 #?
Responda:
#2ln4-ln2=ln8#
Explicação:
As #alnb=lnb^a# e #lnp-lnq=ln(p/q)#
#2ln4-ln2#
= #ln4^2-ln2#
= #ln16-ln2#
= #ln(16/2)=ln8#
#2ln4-ln2=ln8#
As #alnb=lnb^a# e #lnp-lnq=ln(p/q)#
#2ln4-ln2#
= #ln4^2-ln2#
= #ln16-ln2#
= #ln(16/2)=ln8#