Como você encontra a derivada de # y = e ^ (1 / x) #?

#y'=-e^(1/x)/(x^2)#

Explanation :

Using Chain Rule,

Suppose, #y=e^f(x)#

then, #y'=e^f(x)*f'(x)#

Similarly following for the #y=e^(1/x)#

#y'=e^(1/x)*(1/x)'#

#y'=e^(1/x)*(-1/x^2)#

#y'=-e^(1/x)/(x^2)#