Como você resolve cosx = 1 / 2 cosx=12?
Responda:
x=pi/3" or "x=(5pi)/3x=π3 or x=5π3
Explicação:
"since "cosx>0since cosx>0
"then x will be in the first/fourth quadrants"then x will be in the first/fourth quadrants
cosx=1/2cosx=12
rArrx=cos^-1(1/2)=pi/3larrcolor(blue)" angle in first quadrant"⇒x=cos−1(12)=π3← angle in first quadrant
"or "x=(2pi-pi/3)=(5pi)/3larrcolor(blue)" angle in fourth quadrant"or x=(2π−π3)=5π3← angle in fourth quadrant