Como você resolve cosx = 1 / 2 cosx=12?

Responda:

x=pi/3" or "x=(5pi)/3x=π3 or x=5π3

Explicação:

"since "cosx>0since cosx>0

"then x will be in the first/fourth quadrants"then x will be in the first/fourth quadrants

cosx=1/2cosx=12

rArrx=cos^-1(1/2)=pi/3larrcolor(blue)" angle in first quadrant"x=cos1(12)=π3 angle in first quadrant

"or "x=(2pi-pi/3)=(5pi)/3larrcolor(blue)" angle in fourth quadrant"or x=(2ππ3)=5π3 angle in fourth quadrant