How do you solve $y = 2 log (x)$ $y= 2 log(x)$ ?

$x = \sqrt{10^{y}}$ $x=sqrt(10^y)$

$y = 2 log x or y = {log x}^{2}; [{log x}^{m} = m log x]$ $y= 2log x or y= log x^2; [log x^m=mlogx]$

$:. x^2=10^y :. x=sqrt(10^y );$

$[log _b (N)=x$ , Em seguida $b^x=N]$

[Ans]

How do you solve y= 2 log(x)y=2log(x)y= 2 log(x)?