Como você encontra o valor exato do pecado 5Pi / 4?

Responda:

$- \frac{\sqrt{2}}{2}$ $-sqrt2/2$

Explicação:

$\frac{5 π}{4} is situated in the third quadrant hence$ $(5pi)/4" is situated in the third quadrant hence"$

$sin (\frac{5 π}{4}) < 0$ $sin((5pi)/4)<0$

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$\frac{5 π}{4} - π = \frac{π}{4}$ $(5pi)/4-pi=pi/4$

$\Rightarrow sin (\frac{5 π}{4}) = - sin (\frac{π}{4}) = \frac{1}{\sqrt{2}} = \frac{\sqrt{2}}{2}$ $rArrsin((5pi)/4)=-sin(pi/4)=1/sqrt2=sqrt2/2$