Dezembro 23, 2019

por Inger

Como você fatora $2 x^{2} + 3 x = 5$ $2x ^ {2} + 3x = 5$ ?

Responda:

$(x - 1) (2 x + 5) = 0$ $(x-1)(2x+5)=0$

Explicação:

$rearrange equation into standard form$ $"rearrange equation into standard form"$

$\Rightarrow 2 x^{2} + 3 x - 5 = 0 \leftarrow in standard form$ $rArr2x^2+3x-5=0larrcolor(blue)"in standard form"$

$factor the quadratic using the a-c method$ $"factor the quadratic using the a-c method"$

$the factors of - 10 which sum to + 3 are + 5 and - 2$ $"the factors of - 10 which sum to + 3 are + 5 and - 2"$

$2 x^{2} - 2 x + 5 x - 5 = 0 \leftarrow split the middle term$ $2x^2-2x+5x-5=0larrcolor(blue)"split the middle term"$

$2 x (x - 1) + 5 (x - 1) = 0 \leftarrow factor by grouping$ $color(red)(2x)(x-1)color(red)(+5)(x-1)=0larrcolor(blue)"factor by grouping"$

$take out a common factor (x - 1)$ $"take out a common factor "(x-1)$

$(x - 1) (2 x + 5) = 0 \leftarrow factored form$ $(x-1)(color(red)(2x+5))=0larrcolor(blue)"factored form"$