Qual é a derivada de cosec x?
Responda:
-cotxcscx
Explicação:
"differentiate using the "color(blue)"chain rule"
"given "y=f(g(x))" then"
dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"
"here "y=cscx=1/sinx=(sinx)^-1
rArrdy/dx=-(sinx)^-2xxd/dx(sinx)
color(white)(rArrdy/dx)=-cosx/(sin^2x)
color(white)(rArrdy/dx)=-cosx/sinx xx1/sinx
color(white)(rArrdy/dx)=-cotxcscx