Qual é a derivada de cosec x?

Responda:

-cotxcscx

Explicação:

"differentiate using the "color(blue)"chain rule"

"given "y=f(g(x))" then"

dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"

"here "y=cscx=1/sinx=(sinx)^-1

rArrdy/dx=-(sinx)^-2xxd/dx(sinx)

color(white)(rArrdy/dx)=-cosx/(sin^2x)

color(white)(rArrdy/dx)=-cosx/sinx xx1/sinx

color(white)(rArrdy/dx)=-cotxcscx