Como você encontra a derivada de y = ln (5x) y=ln(5x)?
y'=1/x
Explicação
Suppose, y=ln(b(x))
then using Chain Rule,
y'=1/(b(x))*(b(x))'
Similarly following for the above function yields,
y'=1/(5x)*(5x)'
y'=1/(5x)*5
y'=1/x
y'=1/x
Explicação
Suppose, y=ln(b(x))
then using Chain Rule,
y'=1/(b(x))*(b(x))'
Similarly following for the above function yields,
y'=1/(5x)*(5x)'
y'=1/(5x)*5
y'=1/x