Como você fatora: `2x ^ 2 + 7x + 3`?

`"using the a-c method of factorising"`

`"the factors of "2xx3=6`
`"which sum to + 7 are + 6 and + 1"`

`"split the middle term using these factors"`

`rArr2x^2+6x+x+3larrcolor(blue)"factor by grouping"`

`=color(red)(2x)(x+3)color(red)(+1)(x+3)`

`"take out the common factor "(x+3)`

`=(x+3)(color(red)(2x+1))`

`rArr2x^2+7x+3=(x+3)(2x+1)`