Como você fatora: # 2x ^ 2 + 7x + 3 #?

#"using the a-c method of factorising"#

#"the factors of "2xx3=6#
#"which sum to + 7 are + 6 and + 1"#

#"split the middle term using these factors"#

#rArr2x^2+6x+x+3larrcolor(blue)"factor by grouping"#

#=color(red)(2x)(x+3)color(red)(+1)(x+3)#

#"take out the common factor "(x+3)#

#=(x+3)(color(red)(2x+1))#

#rArr2x^2+7x+3=(x+3)(2x+1)#