Como você avalia #sec (pi / 3) #?

# secx = 1/cosx #

#rArr sec(pi/3) = 1/cos(pi/3) #

Using the # pi/3 , pi/6 , pi/2 " triangle " #

with sides of length 1 ,#sqrt3 " and " 2 #

we can obtain the exact value of # cos(pi/3) = 1/2 #

#rArr sec(pi/3) = 1/(1/2) = 2 #