Como você simplifica #Sin (pi / 6 + x) #?
Responda:
#1/2cosx+sqrt3/2sinx#
Explicação:
Using the appropriate#color(blue)" Addition formula "#
#color(red)(|bar(ul(color(white)(a/a)color(black)(sin(A±B)sinAcosB±cosAsinB)color(white)(a/a)|)))#
then #sin(pi/6+x)=sin(pi/6)cosx+cos(pi/6)sinx#
Using the#color(blue)" exact value triangle ""for this angle"#
Then #sin(pi/6)=1/2" and " cos(pi/6)=sqrt3/2#
#rArrsin(pi/6+x)=1/2cosx+sqrt3/2sinx#