Quais são os números de oxidação do carbono no monóxido de carbono e no metanol?

Responda:

Nós temos #:stackrel(II^+)C-=O# contra #H_3stackrel(II^-)COH#, então o metanol tem o carbono com o menor estado de oxidação.

Explicação:

A soma do números de oxidação é igual à carga na molécula e as duas moléculas são neutras.

Aqui estão algumas regras que não precisam ser lembradas, mas precisam ser usadas implicitamente.

#1.# #"The oxidation number of a free element is always 0."#

#2.# #"The oxidation number of a mono-atomic ion is equal"# #"to the charge of the ion."#

#3.# #"For a given bond, X-Y, the bond is split to give "X^+# #"and"# #Y^-#, #"where Y is more electronegative than X."#

#4.# #"The oxidation number of H is +1, but it is -1 in when"# #"combined with less electronegative elements."#

#5.# #"The oxidation number of O in its"# compostos #"is usually -2, but it is -1 in peroxides."#

#6.# #"The oxidation number of a Group 1 element in a"# #"compound is +1."#

#7.# #"The oxidation number of a Group 2 element in a"# #"compound is +2."#

#8.# #"The oxidation number of a Group 17 element in a binary"# #"compound is -1."#

#"9."# #"The SUM of the oxidation numbers of all of the"# #"atoms in a neutral compound is ZERO."#

#10.# #"The SUM of the oxidation numbers in a polyatomic ion"# #"is equal to the charge of the ion."#

Deixe um comentário