Como você fatora # x ^ 2-5x #?

The first consideration is to check if there is a #color(blue)"common factor"#

#x^2=color(red)(x)xx x" and " 5x=5xxcolor(red)(x)#

#"Hence there is a common factor of " color(red)(x)# which can be taken out of each term.

#rArrcolor(red)(x)(x-5)" is the factored form"#

#color(blue)"Check"# by multiplying out.

#rArrx(x-5)=(x xx x)-(5xx x)=x^2-5x#