Março 15, 2020

Qual é a derivada de $y = sec (x^{2})$ $y = sec (x ^ 2)$ ?

$y'=2x*sec(x^2)tan(x^2)$

Solution

let's $y=f(g(x))$

Using Chain Rule, we get

$y'=f'(g(x))*g'(x)$

for given problem, which is

$y=sec(x^2)$

differentiating with respect to $x$ using Chain Rule,

$y'=sec(x^2)tan(x^2)*(x^2)'$

$y'=sec(x^2)tan(x^2)*2x$

$y'=2x*sec(x^2)tan(x^2)$

Qual é a derivada de y = sec (x ^ 2) y=sec(x2) y = sec (x ^ 2) ?

Qual é a derivada de $y = sec (x^{2})$ $y = sec (x ^ 2)$ ?